Initialize char array to hold non-null-terminated string [duplicate]

Question

I am trying to initialize a char array with a long string. However, I do not want it to be NULL terminated.

This:

const char s[] = "The actual string is much longer then this...";

is much easier to read (and to write) than this:

const char s[] = {'T', 'h', 'e', ' ', 'a', 'c', 't', 'u', 'a', 'l', ' ', 's', ...};

but the former gets NULL terminated. Is there a way to avoid the NULL on a string literal?

The reason for doing this is that there is the need to pack densely strings in memory of fixed size length known during development.

Answer 1

No.

A string literal is a C-string which, by definition, is null-terminated.

Either ignore the final character, revisit your requirements (why do you care about a final character?!) or … I dunno, something else. Perhaps generate the objects with xxd?