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I am trying to initialize a 2D array, in which the type of each element is char. So far, I can only initialize this array in the follow way.
public class ticTacToe { private char[][] table; public ticTacToe() { table[0][0] = '1'; table[0][1] = '2'; table[0][2] = '3'; table[1][0] = '4'; table[1][1] = '5'; table[1][2] = '6'; table[2][0] = '7'; table[2][1] = '8'; table[2][2] = '9'; } } I think if the array is 10*10, it is the trivial way. Is there any efficient way to do that?
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Initialization of 2D Array There are two ways to initialize a two Dimensional arrays during declaration. int disp[2][4] = { {10, 11, 12, 13}, {14, 15, 16, 17} }; OR. int disp[2][4] = { 10, 11, 12, 13, 14, 15, 16, 17};
On the other hand, to initialize a 2D array, you just need two nested loops. 6) In a two dimensional array like int[][] numbers = new int[3][2], there are three rows and two columns. You can also visualize it like a 3 integer arrays of length 2.
A two-dimensional array in C can be thought of as a matrix with rows and columns. The general syntax used to declare a two-dimensional array is: A two-dimensional array is an array of several one-dimensional arrays. Following is an array with five rows, each row has three columns: int my_array[5][3];
Shorter way is do it as follows:
private char[][] table = {{'1', '2', '3'}, {'4', '5', '6'}, {'7', '8', '9'}}; If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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