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initialization makes pointer from integer without a cast

Okay, I am having a hard time with this. I've searched for the past hour on it and I don't get what I am doing wrong. I'm trying to take the currentTitle of a sender, then convert it to an integer so I can use it in a call to list.

NSString *str = [sender currentTitle];
NSInteger *nt = [str integerValue]; // this is where the error appears //
NSString *nextScreen = [NSString stringWithFormat:@"Screen_%@.jpg", [screenList objectAtIndex:nt]];

I assume it's something with the [str integerValue] bit not being properly used, but I can't find an example that works.

Thanks!

like image 934
Eric Avatar asked Nov 15 '10 18:11

Eric


1 Answers

Let's analyze the error message:

Initialization (NSInteger nt) makes pointer (*) from integer ([str integerValue]) without a cast.

This means that you are trying to assign a variable of non-pointer type ([str integerValue], which returns an NSInteger) to a variable of pointer type. (NSInteger *).

Get rid of the * after NSInteger and you should be okay:

NSString *str = [sender currentTitle];
NSInteger nt = [str integerValue]; // this is where the error appears //
NSString *nextScreen = [NSString stringWithFormat:@"Screen_%@.jpg", [screenList objectAtIndex:nt]];

NSInteger is a type wrapper for the machine-dependent integral data type, which is defined like so:

#if __LP64__ || (TARGET_OS_EMBEDDED && !TARGET_OS_IPHONE) || TARGET_OS_WIN32 || NS_BUILD_32_LIKE_64
typedef long NSInteger;
typedef unsigned long NSUInteger;
#else
typedef int NSInteger;
typedef unsigned int NSUInteger;
#endif
like image 50
Jacob Relkin Avatar answered Nov 02 '22 23:11

Jacob Relkin