i am using Django to create a user and an object when the user is created. But there is an error
__init__() got an unexpected keyword argument 'user'
when calling the register()
function in view.py. The function is:
def register(request): '''signup view''' if request.method=="POST": form=RegisterForm(request.POST) if form.is_valid(): username=form.cleaned_data["username"] email=form.cleaned_data["email"] password=form.cleaned_data["password"] user=User.objects.create_user(username, email, password) user.save() return HttpResponseRedirect('/keenhome/accounts/login/') else: form = RegisterForm() return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request)) #This is used for reinputting if failed to register else: form = RegisterForm() return render_to_response("polls/register.html", {'form':form}, context_instance=RequestContext(request))
and the object class is:
class LivingRoom(models.Model): '''Living Room object''' user = models.OneToOneField(User) def __init__(self, temp=65): self.temp=temp TURN_ON_OFF = ( ('ON', 'On'), ('OFF', 'Off'), ) TEMP = ( ('HIGH', 'High'), ('MEDIUM', 'Medium'), ('LOW', 'Low'), ) on_off = models.CharField(max_length=2, choices=TURN_ON_OFF) temp = models.CharField(max_length=2, choices=TEMP) #signal function: if a user is created, add control livingroom to the user def create_control_livingroom(sender, instance, created, **kwargs): if created: LivingRoom.objects.create(user=instance) post_save.connect(create_control_livingroom, sender=User)
The Django error page notifies the error information: user=User.objects.create_user(username, email, password)
and LivingRoom.objects.create(user=instance)
I tried to search this problem, finding some cases, but still cannot figure out how to solve it.
You can't do
LivingRoom.objects.create(user=instance)
because you have an __init__
method that does NOT take user
as argument.
You need something like
#signal function: if a user is created, add control livingroom to the user def create_control_livingroom(sender, instance, created, **kwargs): if created: my_room = LivingRoom() my_room.user = instance
Update
But, as bruno has already said it, Django's models.Model
subclass's initializer is best left alone, or should accept *args
and **kwargs
matching the model's meta fields.
So, following better principles, you should probably have something like
class LivingRoom(models.Model): '''Living Room object''' user = models.OneToOneField(User) def __init__(self, *args, temp=65, **kwargs): self.temp = temp return super().__init__(*args, **kwargs)
Note - If you weren't using temp
as a keyword argument, e.g. LivingRoom(65)
, then you'll have to start doing that. LivingRoom(user=instance, temp=66)
or if you want the default (65), simply LivingRoom(user=instance)
would do.
I got the same error.
On my view I was overriding get_form_kwargs() like this:
class UserAccountView(FormView): form_class = UserAccountForm success_url = '/' template_name = 'user_account/user-account.html' def get_form_kwargs(self): kwargs = super(UserAccountView, self).get_form_kwargs() kwargs.update({'user': self.request.user}) return kwargs
But on my form I failed to override the init() method. Once I did it. Problem solved
class UserAccountForm(forms.Form): first_name = forms.CharField(label='Your first name', max_length=30) last_name = forms.CharField(label='Your last name', max_length=30) email = forms.EmailField(max_length=75) def __init__(self, *args, **kwargs): user = kwargs.pop('user') super(UserAccountForm, self).__init__(*args, **kwargs)
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