I'm just learning Haskell. I thought this would produce a factorial function...
(within ghci)
Prelude> let ft 0 = 1 Prelude> let ft n = n * ft (n - 1) Prelude> ft 5
(hangs indefinitely, until ^C).
Can someone point me in the right direction?
Thanks!
The two separate let
statements are interpreted independently from each other. First a function ft 0 = 1
is defined, and then a new function ft n = n * ft (n - 1)
is defined, overwriting the first definition.
To define one function with two cases you have to put both cases into a single let
statement. To do this in a single line at the GHCI prompt you can separate the two cases by ;
:
Prelude> let ft 0 = 1; ft n = n * ft (n - 1) Prelude> ft 5 120
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