I am writing a script for a Google Docs Spreadsheet to read a list of directors and add them to an array if they do not already appear within it.
However, I cannot seem to get indexOf to return anything other than -1 for elements that are contained within the array.
Can anyone tell me what I am doing wrong? Or point me to an easier way of doing this?
This is my script:
function readRows() {
var column = SpreadsheetApp.getActiveSpreadsheet().getRangeByName("Director");
var values = column.getValues();
var numRows = column.getNumRows();
var ss = SpreadsheetApp.getActiveSpreadsheet();
var sheet = ss.getSheets()[0];
var directors = new Array();
for (var i = 0; i <= numRows - 1; i++) {
var row = values[i];
if (directors.indexOf(row) == -1) {
directors.push(row);
} else {
directors.splice(directors.indexOf(row), 1, row);
}
}
for (var i = 2; i < directors.length; i++) {
var cell = sheet.getRange("F" + [i]);
cell.setValue(directors[i]);
}
};
The Array. indexOf() method returns the index of the first matching item in an array (or -1 if it doesn't exist). var wizards = ['Gandalf', 'Radagast', 'Saruman', 'Alatar']; // Returns 1 wizards.
IndexOf(Array, Object, Int32) Searches for the specified object in a range of elements of a one-dimensional array, and returns the index of its first occurrence. The range extends from a specified index to the end of the array.
indexOf does work and does do what you say it does. If you're getting this error, it might mean you've mixed up source and destination (the array before the dot is the one being searched), or you have another subtle programming error (like you aren't comparing the array you think you're comparing).
The indexOf() method returns the position of the first occurrence of a value in a string. The indexOf() method returns -1 if the value is not found. The indexOf() method is case sensitive.
I ran into a similar problem with a spreadsheet function that took a range as an object. In my case, I was wanting to do a simple search for a fixed set of values (in another array).
The problem is, your "column" variable doesn't contain a column -- it contains a 2D array. Therefore, each value is it's own row (itself an array).
I know I could accomplish the following example using the existing function in the spreadsheet, but this is a decent demo of dealing with the 2D array to search for a value:
function flatten(range) {
var results = [];
var row, column;
for(row = 0; row < range.length; row++) {
for(column = 0; column < range[row].length; column++) {
results.push(range[row][column]);
}
}
return results;
}
function getIndex(range, value) {
return flatten(range).indexOf(value);
}
So, since I wanted to simply search the entire range for the existance of a value, I just flattened it into a single array. If you really are dealing with 2D ranges, then this type of flattening and grabbing the index may not be very useful. In my case, I was looking through a column to find the intersection of two sets.
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