In Python, is object() equal to anything besides itself?

Question

If I have the code my_object = object() in Python, will my_object be equal to anything except for itself?

I suspect the answer lies in the __eq__ method of the default object returned by object(). What is the implementation of __eq__ for this default object?

EDIT: I'm using Python 2.7, but am also interested in Python 3 answers. Please clarify whether your answer applies to Python 2, 3, or both.

Answer 1

object().__eq__ returns the NotImplemented singleton:

print(object().__eq__(3))
NotImplemented

By the reflexive rules of rich comparisons, when NotImplemented is returned, the "reflected" operation is tried. So if you have an object on the RHS that returns True for that comparison, then you can get a True response even though the LHS did not implement the comparison.

class EqualToEverything(object):
    def __eq__(self,other):
        return True

ete = EqualToEverything()

ete == object() # we implemented `ete.__eq__`, so this is obviously True
Out[74]: True

object() == ete # still True due to the reflexive rules of rich comparisons
Out[75]: True

python 2 specific bit: if neither object implements __eq__, then python moves on to check if either implement __cmp__. Equivalent reflexive rules apply here.

class ComparableToEverything(object):
    def __cmp__(self,other):
        return 0

cte = ComparableToEverything()

cte == object()
Out[5]: True

object() == cte
Out[6]: True

__cmp__ is gone in python 3.

In both python 2 and 3, when we exhaust all of these comparison operators and all are NotImplemented, the final fallback is checking identity. (a is b)