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In Perl, how can I get the matched substring from a regex?

Tags:

regex

perl

My program read other programs source code and colect information about used SQL queries. I have problem with getting substring.

...
$line = <FILE_IN>;
until( ($line =~m/$values_string/i && $line !~m/$rem_string/i) || eof )
{
   if($line =~m/ \S{2}DT\S{3}/i)
   {

   # here I wish to get (only) substring that match to pattern \S{2}DT\S{3} 
   # (7 letter table name) and display it.
      $line =~/\S{2}DT\S{3}/i;
      print $line."\n";
...

In result print prints whole line and not a substring I expect. I tried different approach, but I use Perl seldom and probably make basic concept error. ( position of tablename in line is not fixed. Another problem is multiple occurrence i.e.[... SELECT * FROM AADTTAB, BBDTTAB, ...] ). How can I obtain that substring?

like image 905
kato sheen Avatar asked Jul 15 '09 15:07

kato sheen


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How do you get a matched string in Perl?

Simple word matching In this statement, World is a regex and the // enclosing /World/ tells Perl to search a string for a match. The operator =~ associates the string with the regex match and produces a true value if the regex matched, or false if the regex did not match.


2 Answers

Use grouping with parenthesis and store the first group.

if( $line =~ /(\S{2}DT\S{3})/i )
{
  my $substring = $1;
}

The code above fixes the immediate problem of pulling out the first table name. However, the question also asked how to pull out all the table names. So:

# FROM\s+     match FROM followed by one or more spaces
# (.+?)       match (non-greedy) and capture any character until...
# (?:x|y)     match x OR y - next 2 matches
# [^,]\s+[^,] match non-comma, 1 or more spaces, and non-comma
# \s*;        match 0 or more spaces followed by a semi colon
if( $line =~ /FROM\s+(.+?)(?:[^,]\s+[^,]|\s*;)/i )
{
  # $1 will be table1, table2, table3
  my @tables = split(/\s*,\s*/, $1);
  # delim is a space/comma
  foreach(@tables)
  {
     # $_ = table name
     print $_ . "\n";
  }
}

Result:

If $line = "SELECT * FROM AADTTAB, BBDTTAB;"

Output:

AADTTAB
BBDTTAB

If $line = "SELECT * FROM AADTTAB;"

Output:

AADTTAB

Perl Version: v5.10.0 built for MSWin32-x86-multi-thread

like image 178
Jesse Vogt Avatar answered Sep 19 '22 19:09

Jesse Vogt


I prefer this:

my ( $table_name ) = $line =~ m/(\S{2}DT\S{3})/i;

This

  1. scans $line and captures the text corresponding to the pattern
  2. returns "all" the captures (1) to the "list" on the other side.

This psuedo-list context is how we catch the first item in a list. It's done the same way as parameters passed to a subroutine.

my ( $first, $second, @rest ) = @_;


my ( $first_capture, $second_capture, @others ) = $feldman =~ /$some_pattern/;

NOTE:: That said, your regex assumes too much about the text to be useful in more than a handful of situations. Not capturing any table name that doesn't have dt as in positions 3 and 4 out of 7? It's good enough for 1) quick-and-dirty, 2) if you're okay with limited applicability.

like image 43
Axeman Avatar answered Sep 16 '22 19:09

Axeman