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In Java: How to zip file from byte[] array?

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java

zip

People also ask

Can you print [] byte?

You can simply iterate the byte array and print the byte using System. out. println() method.

Can we convert byte array to file in Java?

Convert byte[] array to File using Java In order to convert a byte array to a file, we will be using a method named the getBytes() method of String class. Implementation: Convert a String into a byte array and write it in a file.

How do I read a byte array ZIP file?

The ZIP file does not need to be unzipped, so ZipInputStream is not necessary. Use a FileInputStream to read the ZIP file and a ByteArrayOutputStream to write its contents to. Get the latter's byte[]. Use ByteArrayInputStream and FileOutputStream to reverse the process.


You can use Java's java.util.zip.ZipOutputStream to create a zip file in memory. For example:

public static byte[] zipBytes(String filename, byte[] input) throws IOException {
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    ZipOutputStream zos = new ZipOutputStream(baos);
    ZipEntry entry = new ZipEntry(filename);
    entry.setSize(input.length);
    zos.putNextEntry(entry);
    zos.write(input);
    zos.closeEntry();
    zos.close();
    return baos.toByteArray();
}

I have the same problem but i needed a many files in a zip.

 protected byte[] listBytesToZip(Map<String, byte[]> mapReporte) throws IOException {
    String extension = ".pdf";
    ByteArrayOutputStream baos = new ByteArrayOutputStream();
    ZipOutputStream zos = new ZipOutputStream(baos);
    for (Entry<String, byte[]> reporte : mapReporte.entrySet()) {
        ZipEntry entry = new ZipEntry(reporte.getKey() + extension);
        entry.setSize(reporte.getValue().length);
        zos.putNextEntry(entry);
        zos.write(reporte.getValue());
    }
    zos.closeEntry();
    zos.close();
    return baos.toByteArray();
}

You can create a zip file from byte array and return to ui streamedContent

public StreamedContent getXMLFile() {
        try {
            byte[] blobFromDB= null;
            ByteArrayOutputStream baos = new ByteArrayOutputStream();
            ZipOutputStream zos = new ZipOutputStream(baos);
            String fileName= "fileName";
            ZipEntry entry = new ZipEntry(fileName+".xml");
            entry.setSize(byteArray.length);
            zos.putNextEntry(entry);
            zos.write(byteArray);
            zos.closeEntry();
            zos.close();
            InputStream is = new ByteArrayInputStream(baos.toByteArray());
            StreamedContent zipedFile= new DefaultStreamedContent(is,   "application/zip", fileName+".zip", Charsets.UTF_8.name());
            return fileDownload;
        } catch (IOException e) {
            LOG.error("IOException e:{} ",e.getMessage());
        } catch (Exception ex) {
            LOG.error("Exception ex:{} ",ex.getMessage());
        }
}