In C++14 can a constexpr member change a data member?

Question

In C++14, since constexpr are not implicitly const anymore, can a constexpr member function modify a data member of a class:

struct myclass
{
    int member;
    constexpr myclass(int input): member(input) {}
    constexpr void f() {member = 42;} // Is it allowed?
};

Answer 1

Yes they are, I believe this change started with proposal N3598: constexpr member functions and implicit const and eventually became part of N3652: Relaxing constraints on constexpr functions which changed section 7.1.5 paragraph 3 what is allowed in the function body from a white-list:

its function-body shall be = delete, = default, or a compound-statement that contains only

• null statements,
• static_assert-declarations
• typedef declarations and alias-declarations that do not define classes or enumerations,
• using-declarations,
• using-directives,
• and exactly one return statement;

to a black-list:

its function-body shall be = delete, = default, or a compound-statement that does not contain

• an asm-definition,
• a goto statement,
• a try-block, or
• a definition of a variable of non-literal type or of static or thread storage duration or for which no initialization is performed.

and also added the following notes to section C.3.3 Clause 7: declarations:

Change: constexpr non-static member functions are not implicitly const member functions.

Rationale: Necessary to allow constexpr member functions to mutate the object.

Effect on original feature: Valid C++ 2011 code may fail to compile in this International Standard. For example, the following code is valid in C++ 2011 but invalid in this International Standard because it declares the same member function twice with different return types:

struct S {
 constexpr const int &f();
 int &f();
};