Menu
How do you declare a particular member of a struct as volatile?
643
typedef struct{ volatile uint8_t bar; } foo_t; foo_t foo_inst; I recognize that declaring a pointer-typed variable as volatile (e.g. volatile uint8_t * foo) merely informs the compiler that the address pointed-to by foo may change, while making no statement about the values pointed to by foo.
C's volatile keyword is a qualifier that is applied to a variable when it is declared. It tells the compiler that the value of the variable may change at any time--without any action being taken by the code the compiler finds nearby.
The volatile structure is a member of a non-volatile structure, a pointer to which is used to access a register.
A volatile keyword in C is nothing but a qualifier that is used by the programmer when they declare a variable in source code. It is used to inform the compiler that the variable value can be changed any time without any task given by the source code. Volatile is usually applied to a variable when we are declaring it.
Exactly the same as non-struct fields:
#include <stdio.h> int main (int c, char *v[]) { struct _a { int a1; volatile int a2; int a3; } a; a.a1 = 1; a.a2 = 2; a.a3 = 3; return 0; } You can mark the entire struct as volatile by using "volatile struct _a {...}" but the method above is for individual fields.
171
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
