Ignore certain properties in an interface while creating an object in typescript?

Question

I have interface defined with some properties. I want to create an object from this interface, however while creating I don't want to fully initialize all the properties mentioned in the interface. I just want to initialize few. How can I achieve that? Thank you.

export interface Campaign {
  id: string;
  name: string;
  createdOn: string;
  lastUpdated: string;
  createdBy: User;
  type: CampaignType;
  status: CampaignStatus;
  startDate: string;
  endDate: string;
  budget: number;
  description: string;
  account: Account;
}

i want to create an array of campaign objects. this is what i am trying to do .

let campaigns: Campaign[] = [
    {  id:"1",
       name: "test campaign"
      }

   ];

however i get the following error .

Type '{ id: string; name: string; }' is missing the following properties from type 'Campaign': createdOn, lastUpdated, createdBy, type, and 6 more.ts(2740)

Answer 1

if you make the optional properties nullable it should work.

example:

type User = {
  firstName: string;
  lastName?: string;
};

// We can assign a string to the "lastName" property
let john: User = { firstName: "John", lastName: "Doe" };

// ... or we can explicitly assign the value undefined
let jane: User = { firstName: "Jane", lastName: undefined };

// ... or we can not define the property at all
let jake: User = { firstName: "Jake" };