Ifelse statement in R with multiple conditions

Question

With the following sample data I'm trying to create a new variable "Den" (value "0" or "1") based on the values of three conditional variables (Denial1, Denial2, and Denial3).

I want a "0" if ANY of the three conditional variables has a "0" and a "1" only if EACH conditional variable that has a value in it has a value of "1" (e.g., isn't NA).

structure(list(Denial1 = NA_real_, Denial2 = 1, Denial3 = NA_real_,  Den = NA), .Names = c("Denial1", "Denial2", "Denial3", "Den" ), row.names = 1L, class = "data.frame") 

I've tried both of the following commands that result in a missing value NA for "Den":

DF$Den<-ifelse (DF$Denial1 < 1 | DF$Denial2 < 1 | DF$Denial3 < 1, "0", "1")  DF$Den<-ifelse(DF$Denial1 < 1,"0", ifelse (DF$Denial2 < 1,"0", ifelse(DF$Denial3 < 1,"0", "1"))) 

Could someone demonstrate how to do this?

Answer 1

Based on suggestions from @jaimedash and @Old_Mortality I found a solution:

DF$Den <- ifelse(DF$Denial1 < 1 & !is.na(DF$Denial1) | DF$Denial2 < 1 &   !is.na(DF$Denial2) | DF$Denial3 < 1 & !is.na(DF$Denial3), "0", "1") 

Then to ensure a value of NA if all values of the conditional variables are NA:

DF$Den <- ifelse(is.na(DF$Denial1) & is.na(DF$Denial2) & is.na(DF$Denial3),  NA, DF$Den) 

Answer 2

How about?

DF$Den<-ifelse (is.na(DF$Denial1) | is.na(DF$Denial2) | is.na(DF$Denial3), "0", "1")