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what is the code for smarty for if (!isset($var)){ ?
if using {if $x eq '5'} when $x is not defined in smarty , it gives an error function call 'get_template_vars' is unknown or deprecated. . this is what i believe so far as i lost hope in trying to know where did this error come from !
Thanky you .
619
{if} statements in Smarty have much the same flexibility as PHP if statements, with a few added features for the template engine. Every {if} must be paired with a matching {/if} . {else} and {elseif} are also permitted. All PHP conditionals and functions are recognized, such as ||, or, &&, and, is_array(), etc.
Answer: Use the PHP isset() function You can use the PHP isset() function to test whether a variable is set or not. The isset() will return FALSE if testing a variable that has been set to NULL .
The isset() function checks whether a variable is set, which means that it has to be declared and is not NULL. This function returns true if the variable exists and is not NULL, otherwise it returns false.
The isset() function is an inbuilt function in PHP which checks whether a variable is set and is not NULL. This function also checks if a declared variable, array or array key has null value, if it does, isset() returns false, it returns true in all other possible cases.
{if ! isset($var)} body must be at least 30 characters. :) {/if} Try this.
{if $missing_var|default:FALSE} NOT MISSING {else} MISSING {/if} If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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