If [] is [] and Array.prototype is [] why doesn't ([] == Array.prototype)

Question

I'm messing around in console and saw the following:

>>> []
[]
>>> Array.prototype
[]
>>> [] == Array.prototype
false
>>> [] === Array.prototype
false

Can anyone explain this behavior? (Sounds like a good candidate for wtfjs)

Answer 1

In Javascript, == on arrays is pointer equality, ie only true if the both arrays are the same object. If arrays aren't pointer equal, then storing to one won't affect the other.

Answer 2

>>> typeof [] == typeof Array.prototype
true