If greater than batch files

Question

I wrote a simple batch file to run Frequently Used websites based on a number selection. Here's the code I have. I am trying to set it so if someone inputs a number 6 or greater it will go to :N but whenever I type 6 the batch file exits. I have tried if %input% > 6 goto :N but it just tells me I am going to Google.

@echo off :Start2  cls goto Start :Start title Frequently Used Websites echo Please select a website from the list echo with the corresponding key echo -------------------------------------- echo [1] Google echo [2] Wikipedia echo [3] Facebook echo [4] Youtube echo [5] Yahoo set input= set /p input= Choice: if %input%==1 goto Z if NOT goto Start2 if %input%==2 goto X if NOT goto Start2 if %input%==3 goto C if NOT goto Start2 if %input%==4 goto V if NOT goto Start2 if %input%==5 goto B if NOT goto Start2 if %input%>=6 goto N  :Z cls echo You have selected Google pause start www.google.com exit :X cls echo You have selected Wikipedia pause start www.wikipedia.com exit :C cls echo You have selected Facebook pause start www.facebook.com exit :V cls echo You have selected Youtube pause start www.youtube.com exit :B cls echo You have selected Yahoo pause start www.Yahoo.com exit :N cls echo Invalid Selection! Try again pause goto :start2 

Answer 1

try this:

if 3 gtr 2 @echo "biggger" 

This outputs:

"biggger" 

The other operators are:

EQU - equal
NEQ - not equal
LSS - less than
LEQ - less than or equal
GTR - greater than
GEQ - greater than or equal

Reference

• Microsoft TechNet | Windows Server 2012 | Command-line Reference: If (Archived here)
• SS64: If (Archived here)

Answer 2

    if %var% geq 1 

is the easiest way