Let's say, given C++17's if constexpr
and Concepts TS (for instance, in recent gcc versions), we'd like to check if a type in a template function has a nested type:
#include <iostream>
struct Foo { using Bar = int; };
template<typename T>
void doSmth(T)
{
if constexpr (requires { typename T::Bar; })
std::cout << "has nested! " << typename T::Bar {} << std::endl;
else
std::cout << "no nested!" << std::endl;
}
int main()
{
doSmth(Foo {});
//doSmth(0);
}
The documentation for concepts is scarce, so I might have got it wrong, but seems like that's it (and the live example is on Wandbox).
Now let's consider what should happen when uncommenting the other doSmth
call. It seems reasonable to expect that the requires-clause would evaluate to false
, and the else
branch of the if constexpr
will be taken. Contrary to that, gcc makes this a hard error:
prog.cc: In instantiation of 'void doSmth(T) [with T = int]':
prog.cc:17:13: required from here
prog.cc:8:5: error: 'int' is not a class, struct, or union type
if constexpr (requires { typename T::Bar; })
^~
Is that a bug in gcc, or is that the intended behaviour?
Concepts issue 3 ("Allow requires-expressions in more contexts") was given WP status in June. And judging by the current looks of [expr.prim.req], in particular p6:
The substitution of template arguments into a requires-expression may result in the formation of invalid types or expressions in its requirements or the violation of the semantic constraints of those requirements. In such cases, the requires-expression evaluates to
false
; it does not cause the program to be ill-formed.
I'd say your code is fine, and GCC hasn't implemented the resolution of issue 3 properly.
It works starting from C++2a and gcc 10: https://wandbox.org/permlink/qH34tI6oRJ3Ck7Mm
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