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The byte keyword denotes an integral type that stores values as indicated in the following table. It's an Unsigned 8-bit integer.
If it's only 8 bits then how can we assign it to equal 255?
byte myByte = 255;
I thought 8 bits was the same thing as just one character?
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A byte is a group of 8 bits. A bit is the most basic unit and can be either 1 or 0. A byte is not just 8 values between 0 and 1, but 256 (28) different combinations (rather permutations) ranging from 00000000 via e.g. 01010101 to 11111111 . Thus, one byte can represent a decimal number between 0(00) and 255.
A byte has only 8 bits. A bit is a binary digit. So a byte can hold 2 (binary) ^ 8 numbers ranging from 0 to 2^8-1 = 255. It's the same as asking why a 3 digit decimal number can represent values 0 through 999, which is answered in the same manner (10^3 - 1).
bit: a single binary digit, either zero or one. byte: 8 bits, can represent positive numbers from 0 to 255.
In binary, it's all 1's and 0's. So, the step before 256 is all 1's. Therefore, 255 in binary is 11111111. The step before any power of 2 is a string of 1's.
There are 256 different configuration of bits in a byte
0000 0000
0000 0001
0000 0010
...
1111 1111
So can assign a byte a value in the 0-255 range
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