C++03 §4.2 N°1:
An lvalue or rvalue of type “array of N T” or “array of unknown bound of T” can be converted to an rvalue of type “pointer to T.” The result is a pointer to the first element of the array.
What has been confusing in this statement for a long time for me was that I didn't quite understand what an rvalue of array type would mean. That is, I couldn't come up with an expression whose type were an array and the result were an rvalue. I read this thread, which basically asks the same question and the accepted answer is "no, there is no rvalue of array type". I think I just might have a contradiction to this.
C++03 §5.2.5 N°4: (is about expression E1.E2)
If E2 is a non-static data member, and the type of E1 is “cq1 vq1 X”, and the type of E2 is “cq2 vq2 T”,the expression designates the named member of the object designated by the first expression. If E1 is an lvalue, then E1.E2 is an lvalue.
I assume that otherwise it is an rvalue (provided E2 is not a reference, that case is covered by §5.2.5 N°3
) and therefore...
struct A
{
int a[4];
};
A f()
{
A a;
return a;
}
int main()
{
f().a; //I think this is an rvalue of array type...
}
I see two options here:
Option1: I am correct, hurray, yay, cool. In this case the question is: are there other examples?
Option2: I am incorrect, in this case the question is: is this a defect of the standard?
I don't know about 1, but I really doubt about 2 because when they speak about function-to-pointer conversions they mention just lvalues of function types (obviously appreciating that there are no rvalues of such). So it's very likely they had thought abour rvalues of array types.
So, basically my question is whether or not I have come up with an example of rvalue of array type, and if not, please provide a valid one, which I stongly believe there exists.
Arrays are lvalues. The Microsoft documentation is wrong. As an example, the operand of unary & must be a function designator, the result of [] , the result of unary * , or an lvalue (C 2018 6.5.
The answer to this question is no, because an array is composed of several separate array elements that cannot be treated as a whole for assignment purposes. The following statement is therefore illegal: int x, y; x = y; Additionally, you might want to copy the whole array all at once.
Yes, you are correct. The expression is an rvalue of array type. This is not a defect - the committee knows about it, and it was also a common issue in C89, which only allows conversion to pointers for lvalues of array types. As a consequence, you could not index or dereference an array like f().a
. C99 fixed this, and C++ does not have a problem with it.
Note that whether or not it is an rvalue is independent to whether or not the expression denotes an object. C++03 accidentally omitted to say that an rvalue expression that is of array type denotes an object. This was fixed in C++0x by DR#450.
(obviously appreciating that there are no rvalues of such)
There are actually rvalues of function types. These occur for non-static member functions denoted by a class member access expression
struct A { void f(); };
/* A().f is an rvalue of type "void()" */
int main() { A().f(); }
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With