According to this page, there are five ways to assign something to a string:
string (1) string& operator= (const string& str);
c-string (2) string& operator= (const char* s);
character (3) string& operator= (char c);
initializer list (4) string& operator= (initializer_list<char> il);
move (5) string& operator= (string&& str) noexcept;
Then why could I compile the text below? Which of this options was used by compiler?
#include <iostream>
#include <string>
int main()
{
std::string s;
double d = 1.0;
s = d;
std::cout << s << std::endl;
}
And this is not just a senseless question - I've spent long hours trying to find this s = d
assignment in my code. It should have been s = std::to_string(d)
of course.
Compiler: GCC 4.8.4.
We can convert double to String in java using String. valueOf() and Double. toString() methods.
To declare (create) a variable, you will specify the type, leave at least one space, then the name for the variable and end the line with a semicolon ( ; ). Java uses the keyword int for integer, double for a floating point number (a double precision number), and boolean for a Boolean value (true or false).
There are three ways to convert a String to double value in Java, Double. parseDouble() method, Double. valueOf() method and by using new Double() constructor and then storing the resulting object into a primitive double field, autoboxing in Java will convert a Double object to the double primitive in no time.
How do I convert a Double to String? From the apex documentation: Double myDouble = 12.34; String myString = String. valueOf(myDouble);
Your code is equivalent to this code:
#include <iostream>
#include <string>
int main()
{
std::string s;
double d = 1.0;
char j = d;
s = j;
std::cout << s << std::endl;
}
So you will output a \1
followed by a line ending.
If you're using G++, specify -Wconversion
to catch things like this.
f.cpp: In function ‘int main()’:
f.cpp:8:7: warning: conversion to ‘char’ from ‘double’ may alter its value [-Wfloat-conversion]
s = d;
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