I am using HtmlUnit library for Java to manipulate websites programmatically. I can't find the working solution to my problem: How to determine that all AJAX calls are finished and return a completely loaded webpage? Here's what I have tried:
Firstly I create WebClient
instance and make call to my method processWebPage(String url, WebClient webClient)
WebClient webClient = null;
try {
webClient = new WebClient(BrowserVersion.FIREFOX_3_6);
webClient.setThrowExceptionOnScriptError(false);
webClient.setThrowExceptionOnFailingStatusCode(false);
webClient.setJavaScriptEnabled(true);
webClient.setAjaxController(new NicelyResynchronizingAjaxController());
} catch (Exception e) {
System.out.println("Error");
}
HtmlPage currentPage = processWebPage("http://www.example.com", webClient);
And here is my method which should return a completely loaded web page:
private static HtmlPage processWebPage(String url, WebClient webClient) {
HtmlPage page = null;
try {
page = webClient.getPage(url);
} catch (Exception e) {
System.out.println("Get page error");
}
int z = webClient.waitForBackgroundJavaScript(1000);
int counter = 1000;
while (z > 0) {
counter += 1000;
z = webClient.waitForBackgroundJavaScript(counter);
if (z == 0) {
break;
}
synchronized (page) {
System.out.println("wait");
try {
page.wait(500);
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
System.out.println(page.asXml());
return page;
}
That z
variable should return 0
if there are no JavaScript left to load.
Any thoughts? Thanks in advance.
EDIT: I found a partially working solution to my problem, but in this case I should know how the response page looks. For example, if a completely loaded page contains text "complete", my solution would be:
HtmlPage page = null;
int PAGE_RETRY = 10;
try {
page = webClient.getPage("http://www.example.com");
} catch (Exception e) {
e.printStackTrace();
}
for (int i = 0; !page.asXml().contains("complete") && i < PAGE_RETRY; i++) {
try {
Thread.sleep(1000 * (i + 1));
page = webClient.getPage("http://www.example.com");
} catch (Exception e) {
e.printStackTrace();
}
}
But what would be the solution if I don't know how a completely loaded page looks like?
Try this:
HtmlPage page = null;
try {
page = webClient.getPage(url);
} catch (Exception e) {
System.out.println("Get page error");
}
JavaScriptJobManager manager = page.getEnclosingWindow().getJobManager();
while (manager.getJobCount() > 0) {
Thread.sleep(1000);
}
System.out.println(page.asXml());
return page;
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