Simple question:
(How) is it possible to set the value of an <input type="color">
to empty in the colorpicker when selecting such an input in Chrome?
Edit: I want to change the input's value to ""
To achieve disabled state in ColorPicker, set the disabled property to true . The ColorPicker pop-up cannot be accessed in disabled state.
The <input type="color"> defines a color picker. The default value is #000000 (black). The value must be in seven-character hexadecimal notation. Tip: Always add the <label> tag for best accessibility practices!
You can't make it only display hex, but whatever mode the user chooses the value is stored as hex.
I think it cannot be set to be transparent
, but you can modify the start color with value="#colorhex"
.
For example;
<input type="color" value="#0000ff">
http://jsfiddle.net/j3hZB/4/
Edit: It seems that when input
has type="color"
there is always a color defined, and there's no way to set that string to empty.
Although here, the guy with second answer says he figured out a workaround.
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