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Howo to query tables with onetomany and manytoone relationship using Ebean

I am using Play Framework 2.1.0 and Ebean and I am having a problem while querying the following scenarios listed below :

I have 3 classes which represent tables in the database.

class project {
   ...
   @OneToMany
   public SubProject sub;   
}

class SubProject {
   ...
   @ManyToOne
   public Project project;

   @OneToMany 
   public MiniProject mini;    
}   

class MiniProject {
  ...
  @ManyToOne
  public SubProject sub;    
}

Using Ebean, how to

  • retrieve all the subprojects of a list of Projects ?

  • retrieve all the miniprojects of a Project ?

  • given a list of sub projects , how to retrieve all the miniprojects?

like image 897
Santhosh S Avatar asked Oct 22 '22 13:10

Santhosh S


1 Answers

First of all you defined your classes incorrectly. Your @OneToMany annotations should be defined over lists of element. I corrected these mappings and then I wrote test method retrieving desired queries. Here is the code:

Project class:

@Entity  
public class Project {

    @Id
    public Long id;

   @OneToMany(mappedBy="project")
   public List<SubProject> subprojects;
}

SubProject class:

@Entity 
public class SubProject {

    @Id
    public Long id;

    @ManyToOne
    public Project project;

    @OneToMany(mappedBy="subproject") 
    public List<MiniProject> miniprojects; 
} 

MiniProject class:

@Entity 
public class MiniProject {

    @Id
    public Long id;

    @ManyToOne
    public SubProject subproject;
}

Test method:

@Test
public void subTest () {
    FakeApplication app = Helpers.fakeApplication(Helpers.inMemoryDatabase());
    Helpers.start(app);

    Project p1 = new Project();
    p1.id=1L;

    SubProject s1 = new SubProject();
    SubProject s2 = new SubProject();
    s1.id=1L;
    s2.id=2L;

    p1.subprojects.add(s1);
    p1.subprojects.add(s2);
    s1.project = p1;
    s2.project = p1;

    MiniProject m1 = new MiniProject();
    MiniProject m2 = new MiniProject();
    MiniProject m3 = new MiniProject();
    MiniProject m4 = new MiniProject();

    m1.id=1L;
    m2.id=2L;
    m3.id=3L;
    m4.id=4L;

    s1.miniprojects.add(m1);
    s1.miniprojects.add(m2);
    s2.miniprojects.add(m3);
    s2.miniprojects.add(m4);

    m1.subproject =s1;
    m2.subproject =s1;
    m3.subproject =s2;
    m4.subproject =s2;

    Ebean.save(p1);
    Ebean.save(s1);
    Ebean.save(s2); 
    Ebean.save(m1);
    Ebean.save(m2);
    Ebean.save(m3);
    Ebean.save(m4);

    // retrieve all the subprojects of a list of Projects
    List<Long> projectIds = new ArrayList<Long>();
    projectIds.add(1L);     
    List<SubProject> subList = Ebean.createQuery(SubProject.class).where(Expr.in("project.id", projectIds)).findList();

    // retrieve all the miniprojects of a Project 
    Long projectId = 1L;
    List<MiniProject> miniList = Ebean.createQuery(MiniProject.class).where(Expr.eq("subproject.project.id", projectId)).findList();

    // given a list of sub projects , how to retrieve all the miniprojects
    List<Long> subprojectIds = new ArrayList<Long>();
    subprojectIds.add(1L);      
    List<MiniProject> miniSubList = Ebean.createQuery(MiniProject.class).where(Expr.in("subproject.id", subprojectIds)).findList();


    for(SubProject sub: subList) {
        System.out.println("subproject: "+sub.id);
    }
    System.out.println("-----------");
    for(MiniProject mini: miniList) {
        System.out.println("miniproject: "+mini.id);
    }
    System.out.println("-----------");
    for(MiniProject mini: miniSubList) {
        System.out.println("miniproject: "+mini.id);
    }
}
like image 125
rtruszk Avatar answered Oct 24 '22 04:10

rtruszk