How to zip two differently sized lists?

Question

I want to zip two list with different length

for example

A = [1,2,3,4,5,6,7,8,9] B = ["A","B","C"] 

and I expect this

[(1, 'A'), (2, 'B'), (3, 'C'), (4, 'A'), (5, 'B'), (6, 'C'), (7, 'A'), (8, 'B'), (9, 'C')] 

But the build-in zip won't repeat to pair with the list with larger size . Does there exist any build-in way can achieve this? thanks

here is my code

idx = 0 zip_list = [] for value in larger:     zip_list.append((value,smaller[idx]))     idx += 1     if idx == len(smaller):         idx = 0 

Answer 1

You can use itertools.cycle:

Make an iterator returning elements from the iterable and saving a copy of each. When the iterable is exhausted, return elements from the saved copy. Repeats indefinitely.

Example:

A = [1,2,3,4,5,6,7,8,9] B = ["A","B","C"]  from itertools import cycle zip_list = zip(A, cycle(B)) if len(A) > len(B) else zip(cycle(A), B) 

Answer 2

Try this.

A = [1,2,3,4,5,6,7,8,9] B = ["A","B","C"] Z = [] for i, a in enumerate(A):     Z.append((a, B[i % len(B)])) 

Just make sure that the larger list is in A.