How to write regex for bullet space digit and dot

Question

I am using regex for my sentence contains bullet space digit and dot.

• 1. This is sample Application
• 2. This is Sample java program

regex:

•\\s\\d\\.\\s[A-z]

Required output:
This is sample Application.
This is Sample java program.

its not working.Please Suggest me how to do this.

Answer 1

To match the bullet character you will need to use the unicode escape sequence. However Unicode defines several bullet styles, so it's probably best to allow for all of them:

[\u2022,\u2023,\u25E6,\u2043,\u2219]\s\d\.\s[A-z]

This should match the following bullet styles:

• Bullet (•)
• Triangular Bullet (‣)
• White Bullet (◦)
• Hyphen Bullet (⁃)
• Bullet Operator (∙)

Reference: https://en.wikipedia.org/wiki/%E2%80%A2

Answer 2

Instead of using the actual 'bullet,' use the unicode equivalent:

\u2022\s\d\.\s[A-z]

For more info see Unicode Character 'BULLET' (U+2022) and Regex Tutorial - Unicode Characters and Properties

EDIT: To split the lines (assuming each line is a separate string) try this out:

String firstString = "• 1. This is sample Application";
System.out.println(firstString.split("\\u2022\\s\\d\\.\\s")[1]);

This works because String.split cuts your string into an array wherever there's a match. The [1] addresses the second item in that array, being the second half of the split.