How to write a template function that takes an array and an int specifying array size

Question

For a university exercise, I have been asked to write a template function "print();", which takes two arguments, 1: an array of a generic type, and 2: an int specifying the size of the array. The function should then print out every item in the array to the console. I am having some trouble with the function arguments. The code I currently have is:

   template <typename Type>
   Type print (Type a, Type b)
    {
        Type items;
        Type array;
        a = array;
        b = items;

        for (int i = 0; i < items; i++) {
        std::cout << std::endl << "The element of the index " << i << " is " << array << std::endl;
        std::cout << std::endl;
    }

and in main():

    print(Array[], 10);

Obviously putting Array as an argument isn't returning a value, so I am not sure what else to do. Any ideas?

Answer 1

The correct way to write it is

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#include <iostream>

template <typename T, size_t size> void print(const T (&array)[size])
{
    for(size_t i = 0; i < size; ++i)
        std::cout << array[i] << " ";
}

int main() {
    int arr[] = { 1,2,3,4,99};

    print(arr);
}

Prints

1 2 3 4 99