How do I write a switch
statement in Ruby?
The Many Uses Of Ruby Case Statements. Whenever you need to use some if / elsif statements you could consider using a Ruby case statement instead. In this post, you will learn a few different use cases and how it all really works under the hood. Note: In other programming languages this is known as a switch statement.
If you are eager to know how to use an OR condition in a Ruby switch case: So, in a case statement, a , is the equivalent of || in an if statement.
The case statement is a multiway branch statement just like a switch statement in other languages. It provides an easy way to forward execution to different parts of code based on the value of the expression.
Ruby uses the case
expression instead.
case x when 1..5 "It's between 1 and 5" when 6 "It's 6" when "foo", "bar" "It's either foo or bar" when String "You passed a string" else "You gave me #{x} -- I have no idea what to do with that." end
Ruby compares the object in the when
clause with the object in the case
clause using the ===
operator. For example, 1..5 === x
, and not x === 1..5
.
This allows for sophisticated when
clauses as seen above. Ranges, classes and all sorts of things can be tested for rather than just equality.
Unlike switch
statements in many other languages, Ruby’s case
does not have fall-through, so there is no need to end each when
with a break
. You can also specify multiple matches in a single when
clause like when "foo", "bar"
.
case...when
behaves a bit unexpectedly when handling classes. This is due to the fact that it uses the ===
operator.
That operator works as expected with literals, but not with classes:
1 === 1 # => true Fixnum === Fixnum # => false
This means that if you want to do a case ... when
over an object's class, this will not work:
obj = 'hello' case obj.class when String print('It is a string') when Fixnum print('It is a number') else print('It is not a string or number') end
Will print "It is not a string or number".
Fortunately, this is easily solved. The ===
operator has been defined so that it returns true
if you use it with a class and supply an instance of that class as the second operand:
Fixnum === 1 # => true
In short, the code above can be fixed by removing the .class
from case obj.class
:
obj = 'hello' case obj # was case obj.class when String print('It is a string') when Fixnum print('It is a number') else print('It is not a string or number') end
I hit this problem today while looking for an answer, and this was the first appearing page, so I figured it would be useful to others in my same situation.
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With