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I need to write 0x00001234 in the address 0x8000000, is it possible in C?
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So not to happen all these, two variables can't have same addresses not in c, anywhere, you can transfer a variable address to store in a variable, later you will learn more about this topic in pointers in c language, Hope you understood!!
To access address of a variable to a pointer, we use the unary operator & (ampersand) that returns the address of that variable. For example &x gives us address of variable x.
The memcpy function is used to copy a block of data from a source address to a destination address.
To print the memory address, we use '%p' format specifier in C. To print the address of a variable, we use "%p" specifier in C programming language. There are two ways to get the address of the variable: By using "address of" (&) operator.
If you work with hardware register in embedded system then standard way is:
int volatile * const p_reg = (int *) 0x8000000;
*p_reg = 0x1234;
You can have a lot of problems with optimizing compiler, if you omit volatile
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You can, but you will have a segfault 99.9999..9% of the time because your program won't have access on this memory address.
int *nb = (int *) 0x8000000;
*nb = 0x00001234;
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