I have to handle two classes with identical methods but they don't implement the same interface, nor do they extend the same superclass. I'm not able / not allowed to change this classes and I don't construct instances of this classes I only get objects of this. What is the best way to avoid lots of code duplication?
One of the class:
package faa;
public class SomethingA {
private String valueOne = null;
private String valueTwo = null;
public String getValueOne() { return valueOne; }
public void setValueOne(String valueOne) { this.valueOne = valueOne; }
public String getValueTwo() { return valueTwo; }
public void setValueTwo(String valueTwo) { this.valueTwo = valueTwo; }
}
And the other...
package foo;
public class SomethingB {
private String valueOne;
private String valueTwo;
public String getValueOne() { return valueOne; }
public void setValueOne(String valueOne) { this.valueOne = valueOne; }
public String getValueTwo() { return valueTwo; }
public void setValueTwo(String valueTwo) { this.valueTwo = valueTwo; }
}
(In reality these classes are larger)
My only idea is now to create a wrapper class in this was:
public class SomethingWrapper {
private SomethingA someA;
private SomethingB someB;
public SomethingWrapper(SomethingA someA) {
//null check..
this.someA = someA;
}
public SomethingWrapper(SomethingB someB) {
//null check..
this.someB = someB;
}
public String getValueOne() {
if (this.someA != null) {
return this.someA.getValueOne();
} else {
return this.someB.getValueOne();
}
}
public void setValueOne(String valueOne) {
if (this.someA != null) {
this.someA.setValueOne(valueOne);
} else {
this.someB.setValueOne(valueOne);
}
}
public String getValueTwo() {
if (this.someA != null) {
return this.someA.getValueTwo();
} else {
return this.someB.getValueTwo();
}
}
public void setValueTwo(String valueTwo) {
if (this.someA != null) {
this.someA.setValueTwo(valueTwo);
} else {
this.someB.setValueTwo(valueTwo);
}
}
}
But I'm not realy satisfied with this solution. Is there any better / more elegant way to solve this problem?
A better solution would be to create an interface to represent the unified interface to both classes, then to write two classes implementing the interface, one that wraps an A, and another that wraps a B:
public interface SomethingWrapper {
public String getValueOne();
public void setValueOne(String valueOne);
public String getValueTwo();
public void setValueTwo(String valueTwo);
};
public class SomethingAWrapper implements SomethingWrapper {
private SomethingA someA;
public SomethingWrapper(SomethingA someA) {
this.someA = someA;
}
public String getValueOne() {
return this.someA.getValueOne();
}
public void setValueOne(String valueOne) {
this.someA.setValueOne(valueOne);
}
public String getValueTwo() {
return this.someA.getValueTwo();
}
public void setValueTwo(String valueTwo) {
this.someA.setValueTwo(valueTwo);
}
};
and then another class just like it for SomethingBWrapper.
There, a duck-typed solution. This will accept any object with valueOne
, valueTwo
properties and is trivially extensible to further props.
public class Wrapper
{
private final Object wrapped;
private final Map<String, Method> methods = new HashMap<String, Method>();
public Wrapper(Object w) {
wrapped = w;
try {
final Class<?> c = w.getClass();
for (String propName : new String[] { "ValueOne", "ValueTwo" }) {
final String getter = "get" + propName, setter = "set" + propName;
methods.put(getter, c.getMethod(getter));
methods.put(setter, c.getMethod(setter, String.class));
}
} catch (Exception e) { throw new RuntimeException(e); }
}
public String getValueOne() {
try { return (String)methods.get("getValueOne").invoke(wrapped); }
catch (Exception e) { throw new RuntimeException(e); }
}
public void setValueOne(String v) {
try { methods.get("setValueOne").invoke(wrapped, v); }
catch (Exception e) { throw new RuntimeException(e); }
}
public String getValueTwo() {
try { return (String)methods.get("getValueTwo").invoke(wrapped); }
catch (Exception e) { throw new RuntimeException(e); }
}
public void setValueTwo(String v) {
try { methods.get("setValueTwo").invoke(wrapped, v); }
catch (Exception e) { throw new RuntimeException(e); }
}
}
You can use a dynamic proxy to create a "bridge" between an interface you define and the classes that conform but do not implement your interface.
It all starts with an interface:
interface Something {
public String getValueOne();
public void setValueOne(String valueOne);
public String getValueTwo();
public void setValueTwo(String valueTwo);
}
Now you need an InvocationHandler
, that will just forward calls to the method that matches the interface method called:
class ForwardInvocationHandler implements InvocationHandler {
private final Object wrapped;
public ForwardInvocationHandler(Object wrapped) {
this.wrapped = wrapped;
}
@Override
public Object invoke(Object proxy, Method method, Object[] args)
throws Throwable {
Method match = wrapped.getClass().getMethod(method.getName(), method.getParameterTypes());
return match.invoke(wrapped, args);
}
}
Then you can create your proxy (put it in a factory for easier usage):
SomethingA a = new SomethingA();
a.setValueOne("Um");
Something s = (Something)Proxy.newProxyInstance(
Something.class.getClassLoader(),
new Class[] { Something.class },
new ForwardInvocationHandler(a));
System.out.println(s.getValueOne()); // prints: Um
Another option is simpler but requires you to subclass each class and implement the created interface, simply like this:
class SomethingAImpl extends SomethingA implements Something {}
class SomethingBImpl extends SomethingB implements Something {}
(Note: you also need to create any non-default constructors)
Now use the subclasses instead of the superclasses, and refer to them through the interface:
Something o = new SomethingAImpl(); // o can also refer to a SomethingBImpl
o.setValueOne("Uno");
System.out.println(o.getValueOne()); // prints: Uno
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With