In this W3schools example, console.log
on the input element reveals a FileInput object:
FileList {0: File, 1: File, length: 2}
How can I work with this? The example demonstrates accessing the file, but every time a user selects new files, the old files disappear. How can I create a new empty FileList and copy it over, so that a user can add more files to the FileList?
I tried this, but it results in two FileList objects, rather than one FileList with all the files:
var fileStore = x.files;
function myFunction(){
var txt = "";
if ('files' in x) {
if (x.files.length == 0) {
txt = "Select one or more files.";
} else {
fileStore += x.files;
console.log(x.files);
console.log(fileStore);
Just type the word Filelist.exe followed by the full path of the directory that you want to scan. This command creates a list of the files that are located in the Music directory.
In HTML, we will use the type attribute to take input in a form and when we have to take the file as an input, the file value of the type attribute allows us to define an element for the file uploads.
To read a file, use FileReader , which enables you to read the content of a File object into memory. You can instruct FileReader to read a file as an array buffer, a data URL, or text. // Check if the file is an image.
FileList is an object which represents an array of individually selected files from the underlying system.
Untested, but this should work
var fileStore = [];
function myFunction(){
var txt = "";
if ('files' in x) {
if (x.files.length == 0) {
txt = "Select one or more files.";
} else {
fileStore.push.apply(fileStore,x.files);
console.log(x.files);
console.log(fileStore);
More on Function::apply
More on Array::push
It is not possible to add File
objects to FileList
. You can use FormData
to append Files
to a single object.
var data = new FormData();
document.querySelector("input[type=file]")
.addEventListener("change", function(event) {
for (var i = 0, files = event.target.files; i < files.length; i++) {
data.append("file-" + [...data.keys()].length, files[i], files[i].name)
}
})
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