I want to delay progression of a test for T seconds, without generating a timeout.
First I tried the obvious:
sleep(5)
XCTAssert(<test if state is correct after this delay>)
But that failed.
Then I tried:
let promise = expectation(description: "Just wait 5 seconds")
waitForExpectations(timeout: 5) { (error) in
promise.fulfill()
XCTAssert(<test if state is correct after this delay>)
}
My XCTAssert()
now succeeded. But waitForExpectations()
failed with a timeout.
This is according to the documentation of XCTest
wait functions saying:
Timeout is always treated as a test failure.
What are my options?
You can use XCTWaiter.wait functions; for example:
let exp = expectation(description: "Test after 5 seconds")
let result = XCTWaiter.wait(for: [exp], timeout: 5.0)
if result == XCTWaiter.Result.timedOut {
XCTAssert(<test if state is correct after this delay>)
} else {
XCTFail("Delay interrupted")
}
If you know how much time something will take and simply want to wait that duration before continuing the test, you can use this one line:
_ = XCTWaiter.wait(for: [expectation(description: "Wait for n seconds")], timeout: 2.0)
What best worked for me was:
let timeInSeconds = 2.0 // time you need for other tasks to be finished
let expectation = XCTestExpectation(description: "Your expectation")
DispatchQueue.main.asyncAfter(deadline: .now() + timeInSeconds) {
expectation.fulfill()
}
wait(for: [expectation], timeout: timeInSeconds + 1.0) // make sure it's more than what you used in AsyncAfter call.
// do your XCTAssertions here
XCTAssertNotNil(value)
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