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Is the following correct?
var z1=^[0-9]*\d$;
{
if(!z1.test(enrol))
{
alert('Please provide a valid Enrollment Number');
return false;
}
}
Its not currently working on my system.
213
Approach: We have used isNaN() function for validation of the textfield for numeric value only. Text-field data is passed in the function and if passed data is number then isNan() returns true and if data is not number or combination of both number and alphabets then it returns false.
Validating Numeric Ranges. If you're using the regular expression to validate input, you'll probably want to check that the entire input consists of a valid number. To do this, replace the word boundaries with anchors to match the start and end of the string: ^([0-9]|[1-9][0-9]|1[0-9][0-9]|2[0-4][0-9]|25[0-5])$.
To validate a RegExp just run it against null (no need to know the data you want to test against upfront). If it returns explicit false ( === false ), it's broken. Otherwise it's valid though it need not match anything. So there's no need to write your own RegExp validator.
JavaScript | RegExp test() Method The RegExp test() Method in JavaScript is used to test for match in a string. If there is a match this method returns true else it returns false. Where str is the string to be searched.
You can test it as:
/^\d*$/.test(value)
Where:
/ at both ends mark the start and end of the regex^ and $ at the ends is to check the full string than for partial matches\d* looks for multiple occurrences of number charctersYou do not need to check for both \d as well as [0-9] as they both do the same - i.e. match numbers.
153
var numberRegex = /^\s*[+-]?(\d+|\d*\.\d+|\d+\.\d*)([Ee][+-]?\d+)?\s*$/
var isNumber = function(s) {
return numberRegex.test(s);
};
"0" => true
"3." => true
".1" => true
" 0.1 " => true
" -90e3 " => true
"2e10" => true
" 6e-1" => true
"53.5e93" => true
"abc" => false
"1 a" => false
" 1e" => false
"e3" => false
" 99e2.5 " => false
" --6 " => false
"-+3" => false
"95a54e53" => false
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