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I have a form like this located at http://www.sms-online.web.id:
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<body>
<form method="post" enctype="multipart-form-data" name="my_form" onsubmit="clearTextBoxCounter()" action="http://www.sms-online.web.id/kirim" >
<input type=hidden name=teks value=><center><b>KIRIM SMS GRATIS</b></center><br><br>
Nomer:<br />
<input type="text" maxlength="20" name="Phonenumbers" value="08888888"/>
<br />
<br />
Isi:<br />
<textarea rows="5" cols="50" onKeyPress=check_length(this.form); onKeyDown=check_length(this.form); name=Text >
Content of my sms
</textarea>
<br />
<input id="saveForm" class="btTxt" type="submit" value="KIRIM" name="TOMBOL" />
</body>
</html>
I would like to post to that form and then submit it, how do I use wget to do the job? I've read about wget --post-data xxx but I still don't know what I should type in in the terminal, based on that html file, should I type in like this? (I'm really not sure it'll work) wget --post-data value=08585858 textarea="Content of my sms" http://www.sms-online.web.id
248
Wget does not currently support multipart/form-data for transmitting POST data; only application/x-www-form-urlencoded . Only one of ' --post-data ' and ' --post-file ' should be specified. Please note that wget does not require the content to be of the form key1=value1&key2=value2 , and neither does it test for it.
Wget is a networking command-line tool that lets you download files and interact with REST APIs. It supports the HTTP , HTTPS , FTP , and FTPS internet protocols. Wget can deal with unstable and slow network connections. In the event of a download failure, Wget keeps trying until the entire file has been retrieved.
From this SO question:
wget --post-data="value=08585858&textarea=\"Content of sms\"" <url>
Also check this.
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