How to use Tuckey urlrewrite in spring boot to access service using ?wsdl

Question

My clients wanted to access wsdl using ?wsdl notation, but the springboot service i have created is working with only '.wsdl' format. I need a working example/sample how to configure Tuckey urlrewrite in the springboot application. I have tried using below code, but the application complaints as it cant find urlrewrite.xml (which i have placed in src/main/resources folder.

Q1: How can i make my service to be accessible using url below http://localhost:8080/ws/organisation?wsdl

I have tried using below code, but tuckey cannot find the urlrewrite.xml which is under src/java/resources.

@Bean
public FilterRegistrationBean tuckeyRegistrationBean() {
    final FilterRegistrationBean registrationBean = new ilterRegistrationBean();
    registrationBean.setFilter(new UrlRewriteFilter());
    registrationBean.addInitParameter("confPath", "urlrewrite.xml");
    return registrationBean;
}

Answer 1

Finally I could figure out a solution. This is now reading urlrewrite.xml from the src/main/resources folder.

No need to declare above mentioned bean definition in the question post (public FilterRegistrationBean tuckeyRegistrationBean()), as the below code declared as @Component will automatically register with context and url-rewriting is performed.

@Component
public class WsdlUrlRewriteFilter extends UrlRewriteFilter {

    private static final String CONFIG_LOCATION = "classpath:/urlrewrite.xml";

    @Value(CONFIG_LOCATION)
    private Resource resource;

    @Override
    protected void loadUrlRewriter(FilterConfig filterConfig) throws ServletException {
        try {
            Conf conf = new Conf(filterConfig.getServletContext(), resource.getInputStream(), resource.getFilename(), "");
        checkConf(conf);
        } catch (IOException ex) {
            throw new ServletException("Unable to load URL-rewrite configuration file from " + CONFIG_LOCATION, ex);
        }
    }
}

Answer 2

Best option is to write your own filter as follows.You can make use of HttpServletRequestWrapper to handle the ?wsdl extension and let the server handle the request.

import org.springframework.stereotype.Component;

import javax.servlet.*;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletRequestWrapper;
import java.io.IOException;

@Component
public class WSDLQuestionMarkReplaceFilter implements Filter {

    @Override
    public void init(FilterConfig filterConfig) throws ServletException {
        //put init logs
    }

    @Override
    public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        HttpServletRequest httpRequest = (HttpServletRequest) request;
        if ("wsdl".equalsIgnoreCase(httpRequest.getQueryString())) {
            HttpServletRequestWrapper requestWrapper = new HttpServletRequestWrapper(httpRequest) {
                @Override
                public String getQueryString() {
                    return null;
                }

                @Override
                public String getRequestURI() {
                    return super.getRequestURI() + ".wsdl";
                }
            };
            chain.doFilter(requestWrapper, response);
        } else {
            chain.doFilter(request, response);
        }
    }

    @Override
    public void destroy() {
        //put destroy logs
    }
}