How to use templates with QT signals and slots?

Question

I want to use signals and slots in my program, but unfortunately they should be used for transmitting several different data types (e.g. QString, double, etc.) and I don't want to write twenty different slots just because I need one for each data type. But when I want to declare a slot like

template <typename t>
void Slot1(t data);

QT tells me that it is not possible to use templates in signals and slots. Is there a workaround? Or can my approach simply improved?

Answer 1

Accurate answer: It is impossible

Workaround: You can do something like this with new signals and slots syntax:

QSlider *slid = new QSlider;
QLineEdit *lne = new QLineEdit;

connect(slid,&QSlider::valueChanged,this,&MainWindow::random);
connect(lne,&QLineEdit::textChanged,this,&MainWindow::random);
lne->show();
slid->show();

Slot:

void MainWindow::random(QVariant var)
{
    qDebug() << var;
}

Output:

QVariant(int, 11) 
QVariant(int, 12) 
QVariant(int, 13) 
QVariant(int, 14) 
QVariant(int, 16) 
QVariant(QString, "c") 
QVariant(QString, "cv") 
QVariant(QString, "cvb") 
QVariant(QString, "cvbc") 
QVariant(QString, "cvbcv")

Why? http://qt-project.org/wiki/New_Signal_Slot_Syntax

Possibility to automatically cast the types if there is implicit conversion (e.g. from QString to QVariant)

Answer 2

Lambda function could do the trick. For example in your case:

class A : public QObject
{
    Q_OBJECT
signals:
    void signal1();
}

class B : public QObject
{
    Q_OBJECT

    template <typename t>
    void Slot1(t data);
}

A* ptra = new A();
B* ptrb = new B();
connect(ptra, &A::signal1, this, [=](){ptrb->Slot1(666);});

It basically creates a no-name slot in the class that calls the connect function and use this slot to call the template function. In this case, the template function does not have to be a slot.