There are plenty of articles on calling Java varargs from Scala code, but the only thing I could find the opposite way round was this question: Using scala vararg methods in java, which doesn't have any concrete examples.
I'm trying to use scala.Console
from some Java code, for the reason that java.io.Console
doesn't work in Eclipse, whereas the Scala one does. But I cannot get the method
def readLine (text: String, args: Any*): String
to work because it seems to be expecting a scala.collection.Seq[Any]
for the second argument, and I don't see how to create a Seq
in Java. How can I work around this?
Things I've tried:
1) Using null
// Java
String s = scala.Console.readLine("Enter text: ", null);
- get rewarded with a NullPointerException
.
2) Replacing the null
with scala.collection.Seq.empty()
, but javac reports all sorts of errors such as Seq
not having an empty
method.
3) Using the Nil
object in the scala.collection.immutable
package object, but the syntax suggested here, which would be scala.collection.immutable.package$Nil$.MODULE$
, but that can't be resolved.
Of course I could just use the readLine()
method that doesn't take varargs, but that would be too easy.
Important Points regarding Varargs Before JDK 5, variable length arguments could be handled in two ways: One was using overloading, other was using array argument. There can be only one variable argument in a method. Variable argument (Varargs) must be the last argument.
Varargs are useful for any method that needs to deal with an indeterminate number of objects. One good example is String. format . The format string can accept any number of parameters, so you need a mechanism to pass in any number of objects.
Scala varargs: The concept of providing variable-length argument to a method.
As Java cannot determine the type of literal null , you must explicitly inform the type of the literal null to Java. Failing to do so will result in an NullPointerException . For example, the following main method invokes the foo method with literal null .
You can use:
scala.collection.Seq$.MODULE$.empty();
from Java code to create an empty sequence. Otherwise, you can use:
new scala.collection.mutable.ArrayBuffer();
to create an empty array buffer into which you can then add elements and use it as an argument to Scala vararg methods.
Otherwise, if you design a Scala library with vararg methods which you want to use from Java code, then use the varargs
annotation. It will generate a Java version of the method which takes an array instead of a Seq
.
scala> class A {
| @annotation.varargs def foo(x: Int*) { println(x) }
| }
defined class A
scala> println(classOf[A].getMethods.toList)
List(public void $line1.$read$$iw$$iw$A.foo(scala.collection.Seq), public void $line1.$read$$iw$$iw$A.foo(int[]), ...)
Above, reflection shows that there are 2 versions of method foo
generated - one that takes a Seq[Int]
and another which takes an int[]
.
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