How to use regular expressions to parse HTML in Java?

Question

Please can someone tell me a simple way to find href and src tags in an html file using regular expressions in Java?
And then, how do I get the URL associated with the tag?

Thanks for any suggestion.

Answer 1

Using regular expressions to pull values from HTML is always a mistake. HTML syntax is a lot more complex that it may first appear and it's very easy for a page to catch out even a very complex regular expression.

Use an HTML Parser instead. See also What are the pros and cons of the leading Java HTML parsers?

Answer 2

The other answers are true. Java Regex API is not a proper tool to achieve your goal. Use efficient, secure and well tested high-level tools mentioned in the other answers.

If your question concerns rather Regex API than a real-life problem (learning purposes for example) - you can do it with the following code:

String html = "foo <a href='link1'>bar</a> baz <a href='link2'>qux</a> foo";
Pattern p = Pattern.compile("<a href='(.*?)'>");
Matcher m = p.matcher(html);
while(m.find()) {
   System.out.println(m.group(0));
   System.out.println(m.group(1));
}

And the output is:

<a href='link1'>
link1
<a href='link2'>
link2

Please note that lazy/reluctant qualifier *? must be used in order to reduce the grouping to the single tag. Group 0 is the entire match, group 1 is the next group match (next pair of parenthesis).