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How to use PNG's IDAT chunk?

Tags:

php

chunks

png

I'm trying to understand how data are stored into IDAT chunk. I'm writing a little PHP class and I can retrieve most of chunks information but what I get for IDAT doesn't match pixels of my image :

enter image description here It is 2×2px truecolour with alpha (bitdepth 8).

But when I interpret IDAT data like this:

current(unpack('H*',gzuncompress($idat_data)));

I get

00000000ffffff00ffffff000000

I don't understand how it can match pixels. Or is it my code which corrupts data?

Thanks for your help!

EDIT: I get

08d705c101010000008010ff4f1750a93029e405fb

as hex compressed data, so it seems I loss several bytes after uncompressing.

enter image description here

like image 942
MatTheCat Avatar asked Sep 03 '11 11:09

MatTheCat


3 Answers

Use gzinflate but skip the first 2 bytes and the last 4 first.

$contents = file_get_contents($in_filename);
$pos = 8; // skip header

$color_types = array('Greyscale','unknown','Truecolour','Indexed-color','Greyscale with alpha','unknown','Truecolor with alpha');
$len = strlen($contents);
$safety = 1000;
do {
    list($unused,$chunk_len) = unpack('N', substr($contents,$pos,4));

    $chunk_type = substr($contents,$pos+4,4);

    $chunk_data = substr($contents,$pos+8,$chunk_len);

    list($unused,$chunk_crc) = unpack('N', substr($contents,$pos+8+$chunk_len,4));
    echo "chunk length:$chunk_len(dec) 0x" . sprintf('%08x',$chunk_len) . "h<br>\n";
    echo "chunk crc   :0x" . sprintf('%08x',$chunk_crc) . "h<br>\n";
    echo "chunk type  :$chunk_type<br>\n";
    echo "chunk data  $chunk_type bytes:<br>\n"  . chunk_split(bin2hex($chunk_data)) . "<br>\n";
    switch($chunk_type) {
        case 'IHDR':
        list($unused,$width,$height) = unpack('N2', substr($chunk_data,0,8));
        list($unused,$depth,$Color_type,$Compression_method,$Filter_method,$Interlace_method) = unpack('C*', substr($chunk_data,8));
        echo "Width:$width,Height:$height,depth:$depth,Color_type:$Color_type(" . $color_types[$Color_type] . "),Compression_method:$Compression_method,Filter_method:$Filter_method,Interlace_method:$Interlace_method<br>\n";
        $bytes_per_pixel = $depth / 8;
        break;

        case 'PLTE':
        $palette = array();
        for($i=0;$i<$chunk_len;$i+=3) {
            $tupl = bin2hex(substr($chunk_data,$i,3));
            $palette[] = $tupl;
            if($i && ($i % 30 == 0)) {
                echo "<br>\n";
            }
            echo '<span style="color:' . $tupl . ';">[' . $tupl . ']</span>';
        }
        echo print_r($palette,true) . "<br>";
        break;

        case 'IDAT':
        $compressed = substr($chunk_data,2,$chunk_len - 6); // 2 bytes on the front and 4 at the end
        $decompressed = gzinflate($compressed);
        echo "decompressed chunk data " . strlen($decompressed) . " bytes:<br>\n"  . chunk_split(bin2hex($decompressed),2 + $width * $bytes_per_pixel * 2) . "<br>\n";
        for($row=0; $row<$height; $row++) {
            for($col=1; $col<=$width; $col++) {
                $index = (int)substr($decompressed,((int)$row*($width+1)+$col),1);
                echo '<span style="color:' . $palette[$index] . ';">' . $index . '</span>';
            }
            echo "<br>\n";
        }
        // TODO use filters described here:
        // http://www.w3.org/TR/PNG/#9Filters
        // first byte of scan line is filter type
        break;

    }
    $pos += $chunk_len + 12;
    echo "<hr>";
} while(($pos < $len) && --$safety);
like image 175
Charlie Avatar answered Sep 24 '22 10:09

Charlie


00000000 ffffff00 ffffff00 0000xxxx
black    white    white    black

That's what I can tell (which is correct) ... but you are missing 2 bytes at the end.

like image 23
Andreas Avatar answered Sep 22 '22 10:09

Andreas


To add to @Andreas (+1) parsing, two things to note:

  1. A PNG file can have (and often has) many IDAT chunks, they must be concatenated to recover the compressed zlib stream. http://www.w3.org/TR/PNG/#10CompressionFSL

  2. Gzip/Compress/Deflate are all related but are not exactly the same. PNG uses deflate/inflate. I'd try with gzdeflate/gzinflate

like image 29
leonbloy Avatar answered Sep 25 '22 10:09

leonbloy