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How to use parameters "@" in an SQL command in VB

I have this code to update my SQL database from data in a textbox, in VB. I need to use parameters in case the text contains a tic mark ,', or a quote ,", etc. Here is what I have:

dbConn = New SqlConnection("server=.\SQLEXPRESS;Integrated Security=SSPI; database=FATP")
    dbConn.Open()

    MyCommand = New SqlCommand("UPDATE SeansMessage SET Message = '" & TicBoxText.Text & _
                                            "'WHERE Number = 1", dbConn)

    MyDataReader = MyCommand.ExecuteReader()
    MyDataReader.Close()
    dbConn.Close()

And this is my lame attempt to set a parameter from what I have seen on the web, which I don't understand all that well.

dbConn = New SqlConnection("server=.\SQLEXPRESS;Integrated Security=SSPI; database=FATP")
    dbConn.Open()

    MyCommand = New SqlCommand("UPDATE SeansMessage SET Message = @'" & TicBoxText.Text & _
                                            "'WHERE Number = 1", dbConn)

    MyDataReader = MyCommand.ExecuteReader()
    MyDataReader.Close()
    dbConn.Close()

How do you do this? Cause if there is a ' mark in the textbox when I run the code, it crashes.

like image 588
TitanicSwimmer Avatar asked Jun 21 '12 13:06

TitanicSwimmer


1 Answers

You are on the right path to avoiding Bobby Tables, but your understanding of @ parameters is incomplete.

Named parameters behave like variables in a programming language: first, you use them in your SQL command, and then you supply their value in your VB.NET or C# program, like this:

MyCommand = New SqlCommand("UPDATE SeansMessage SET Message = @TicBoxText WHERE Number = 1", dbConn)
MyCommand.Parameters.AddWithValue("@TicBoxText", TicBoxText.Text)

Note how the text of your command became self-contained: it no longer depends on the value of the text from the text box, so the users cannot break your SQL by inserting their own command. @TicBoxText became a name of the variable that stands for the value in the text of the command; the call to AddWithValue supplies the value. After that, your ExecuteReader is ready to go.

like image 124
Sergey Kalinichenko Avatar answered Sep 29 '22 11:09

Sergey Kalinichenko