How to use onsubmit() to show a confirmation if there are multiple submit buttons on the same form?

Question

<form onsubmit="return confirm('Are you sure you want to rollback deletion of candidate table?')">
<input type='submit' name='delete' value='Undo' />
<input type='submit' name='no' value='No' />

when the user clicks on second submit button i.e No i want to display the confirmation dialogue as "Are you sure you want to commit the transaction."

Answer 1

<form method='post'>
    <input type='submit' name='undo' value='Undo' onclick="return confirm('Are you sure you want to rollback deletion of candidate table?')"/>
    <input type='submit' name='no' value='No' onclick="return confirm('Are you sure you want to commit delete and go back?')"/>
</form>

Worked fine. just changed onsubmit() to onclick(). as the function of both in this situation is same.

Answer 2

You could bind to onclick instead of onsubmit - see below.

<script> 
function submitForm() {
    return confirm('Rollback deletion of candidate table?');
}
<script>

<form>
    <input type='submit' onclick='submitForm()' name='delete' value='Undo' />
    <input type='submit' onclick='submitForm()' name='no' value='No' />
</form>

Or alternately, using jQuery:

<script> 
$(document).ready(function() {
    $('form input[type=submit]').click(function() {
        return confirm('Rollback deletion of candidate table?');
    });
});
<script>