How to use OKHTTP to make a post request?

Question

I read some examples which are posting jsons to the server.

some one says :

OkHttp is an implementation of the HttpUrlConnection interface provided by Java. It provides an input stream for writing content and doesn't know (or care) about what format that content is.

Now I want to make a normal post to the URL with params of name and password.

It means I need to do encode the name and value pair into stream by myself?

Answer 1

As per the docs, OkHttp version 3 replaced FormEncodingBuilder with FormBody and FormBody.Builder(), so the old examples won't work anymore.

Form and Multipart bodies are now modeled. We've replaced the opaque FormEncodingBuilder with the more powerful FormBody and FormBody.Builder combo.

Similarly we've upgraded MultipartBuilder into MultipartBody, MultipartBody.Part, and MultipartBody.Builder.

So if you're using OkHttp 3.x try the following example:

OkHttpClient client = new OkHttpClient();

RequestBody formBody = new FormBody.Builder()
        .add("message", "Your message")
        .build();
Request request = new Request.Builder()
        .url("https://www.example.com/index.php")
        .post(formBody)
        .build();

try {
    Response response = client.newCall(request).execute();

    // Do something with the response.
} catch (IOException e) {
    e.printStackTrace();
}

Answer 2

The current accepted answer is out of date. Now if you want to create a post request and add parameters to it you should user MultipartBody.Builder as Mime Craft now is deprecated.

RequestBody requestBody = new MultipartBody.Builder()
        .setType(MultipartBody.FORM)
        .addFormDataPart("somParam", "someValue")
        .build();

Request request = new Request.Builder()
        .url(BASE_URL + route)
        .post(requestBody)
        .build();