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I need to filter out records based on some text matching in nvarchar(1000) column. Table has more than 400 thousands records and growing. For now, I am using Like condition:-
SELECT
*
FROM
table_01
WHERE
Text like '%A1%'
OR Text like '%B1%'
OR Text like '%C1%'
OR Text like '%D1%'
Is there any preferred work around?
419
The SQL LIKE clause is used to compare a value to similar values using wildcard operators. There are two wildcards used in conjunction with the LIKE operator. The percent sign represents zero, one or multiple characters. The underscore represents a single number or character.
“The SQL LIKE operator allows performing logical evaluation for any matching records. Using the LIKE operator, you can specify single or multiple conditions. This allows you to perform an action such as select, delete, and updating any columns or records that match the specified conditions.
select * from employee where name like '%aa%' or name like '%bb% or name like '%cc%'..... Next row NAME Column Contains aa bb cc dd..... each value in the NAME column and put in the multiple like operator using OR condition.
So, here is the easiest solution. select * from table1 where column1 not like '%value1%' and column1 not like '%value2%' and column1 not like'%value3%'; If you want to play around with the Boolean logic, you rearrange the query like this.
SELECT
*
FROM
table_01
WHERE
Text like '%[A-Z]1%'
This will check if the texts contains A1, B1, C1, D1, ...
Reference to using the Like Condition in SQL Server
195
You can try the following if you know the exact position of your sub string:
SELECT
*
FROM
table_01
WHERE
SUBSTRING(Text,1,2) in ('B1','C1','D1')
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