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how to use HttpsUrlConnection instead of DefaultHttpClient

DefaultHttpClient, ThreadSafeClientConnManager, HttpParams,HttpProtocolParams, SchemeRegistry, SSLSocketFactory, NameValuePair, HttpResponse are deprecated.

I tried to use HttpsUrlConnection but i confused about them.

protected Gson gson;
private ThreadSafeClientConnManager threadSafeClientConnManager;
private DefaultHttpClient client;

AbstractServiceApi() {

    // sets up parameters
    HttpParams params = new BasicHttpParams();
    HttpProtocolParams.setVersion(params, HttpVersion.HTTP_1_1);
    HttpProtocolParams.setContentCharset(params, ENCODING);
    HttpConnectionParams.setConnectionTimeout(params, 95 * 1000);
    HttpConnectionParams.setSoTimeout(params, 95 * 1000);
    HttpConnectionParams.setStaleCheckingEnabled(params, false);
    params.setBooleanParameter("http.protocol.expect-continue", false);

    // registers schemes for both http and https
    SchemeRegistry registry = new SchemeRegistry();
    registry.register(new Scheme("http", PlainSocketFactory.getSocketFactory(), 80));
    SSLSocketFactory sslSocketFactory = SSLSocketFactory.getSocketFactory();
    sslSocketFactory.setHostnameVerifier(SSLSocketFactory.BROWSER_COMPATIBLE_HOSTNAME_VERIFIER);
    registry.register(new Scheme("https", sslSocketFactory, 443));

    threadSafeClientConnManager = new ThreadSafeClientConnManager(params, registry);
    client = new DefaultHttpClient(threadSafeClientConnManager, params);
    gson = new Gson();
}

I don't have an keystore. https://developer.android.com/reference/javax/net/ssl/HttpsURLConnection.html

   KeyStore keyStore = ...;
   String algorithm = TrustManagerFactory.getDefaultAlgorithm();
   TrustManagerFactory tmf = TrustManagerFactory.getInstance(algorithm);
   tmf.init(keyStore);

   SSLContext context = SSLContext.getInstance("TLS");
   context.init(null, tmf.getTrustManagers(), null);

   URL url = new URL("https://www.example.com/");
   HttpsURLConnection urlConnection = (HttpsURLConnection) url.openConnection();
   urlConnection.setSSLSocketFactory(context.getSocketFactory());
   InputStream in = urlConnection.getInputStream();

could anyone help me?

like image 900
Kaloglu Avatar asked Dec 15 '15 15:12

Kaloglu


1 Answers

This is my solution.

private HttpsURLConnection urlConnection;
private CookieManager cookieManager;

private HttpsURLConnection getConnection(String url) throws MalformedURLException {
    URL request_url = new URL(url);
    try {
        if (!isHttps()) {
            throw new ConnectException("you have to use SSL certifacated url!");
        }
        urlConnection = (HttpsURLConnection) request_url.openConnection();
        urlConnection.setRequestMethod("POST");
        urlConnection.setReadTimeout(95 * 1000);
        urlConnection.setConnectTimeout(95 * 1000);
        urlConnection.setDoInput(true);
        urlConnection.setRequestProperty("Accept", "application/json");
        urlConnection.setRequestProperty("X-Environment", "android");

        /** Cookie Sets... */
        String cookie = cookieManager.getCookie(urlConnection.getURL().toString());
        cookieManager = CookieManager.getInstance();
        if (cookie != null)
            urlConnection.setRequestProperty("Cookie", cookie);

        List<String> cookieList = urlConnection.getHeaderFields().get("Set-Cookie");
        if (cookieList != null) {
            for (String cookieTemp : cookieList) {
                cookieManager.setCookie(urlConnection.getURL().toString(), cookieTemp);
            }
        }
        /** Cookie Sets... */

        urlConnection.setHostnameVerifier(new HostnameVerifier() {
            @Override
            public boolean verify(String hostname, SSLSession session) {
                /** if it necessarry get url verfication */
                //return HttpsURLConnection.getDefaultHostnameVerifier().verify("your_domain.com", session);
                return true;
            }
        });
        urlConnection.setSSLSocketFactory((SSLSocketFactory) SSLSocketFactory.getDefault());


        urlConnection.connect();

    } catch (IOException e) {
        e.printStackTrace();
    }

    return urlConnection;
}
like image 66
Kaloglu Avatar answered Nov 15 '22 04:11

Kaloglu