This is my HTML which I'm generating dynamically using drag and drop functionality.
<form method="POST" id="contact" name="13" class="form-horizontal wpc_contact" novalidate="novalidate" enctype="multipart/form-data"> <fieldset> <div id="legend" class=""> <legend class="">file demoe 1</legend> <div id="alert-message" class="alert hidden"></div> </div> <div class="control-group"> <!-- Text input--> <label class="control-label" for="input01">Text input</label> <div class="controls"> <input type="text" placeholder="placeholder" class="input-xlarge" name="name"> <p class="help-block" style="display:none;">text_input</p> </div> <div class="control-group"> </div> <label class="control-label">File Button</label> <!-- File Upload --> <div class="controls"> <input class="input-file" id="fileInput" type="file" name="file"> </div> </div> <div class="control-group"> <!-- Button --> <div class="controls"> <button class="btn btn-success">Button</button> </div> </div> </fieldset> </form>
This is my JavaScript code:
<script> $('.wpc_contact').submit(function(event){ var formname = $('.wpc_contact').attr('name'); var form = $('.wpc_contact').serialize(); var FormData = new FormData($(form)[1]); $.ajax({ url : '<?php echo plugins_url(); ?>'+'/wpc-contact-form/resources/js/tinymce.php', data : {form:form,formname:formname,ipadd:ipadd,FormData:FormData}, type : 'POST', processData: false, contentType: false, success : function(data){ alert(data); } }); }
Uploading Multiple Files const uploadFile = (files) => { console. log("Uploading file..."); const API_ENDPOINT = "https://file.io"; const request = new XMLHttpRequest(); const formData = new FormData(); request. open("POST", API_ENDPOINT, true); request. onreadystatechange = () => { if (request.
Follow this rules when creating a multipart form: Specify enctype="multipart/form-data" attribute on a form tag. Add a name attribute to a single input type="file" tag. DO NOT add a name attribute to any other input, select or textarea tags.
Using this function you can upload a image through the FormData object, available in the XMLHttpRequest Level 2, it uses the same format a form would use if the encoding type were set to "multipart/form-data". the function search for a input[type=file], and get the data in it.
For correct form data usage you need to do 2 steps.
Preparations
You can give your whole form to FormData() for processing
var form = $('form')[0]; // You need to use standard javascript object here var formData = new FormData(form);
or specify exact data for FormData()
var formData = new FormData(); formData.append('section', 'general'); formData.append('action', 'previewImg'); // Attach file formData.append('image', $('input[type=file]')[0].files[0]);
Sending form
Ajax request with jquery will looks like this:
$.ajax({ url: 'Your url here', data: formData, type: 'POST', contentType: false, // NEEDED, DON'T OMIT THIS (requires jQuery 1.6+) processData: false, // NEEDED, DON'T OMIT THIS // ... Other options like success and etc });
After this it will send ajax request like you submit regular form with enctype="multipart/form-data"
Update: This request cannot work without type:"POST"
in options since all files must be sent via POST request.
Note: contentType: false
only available from jQuery 1.6 onwards
I can't add a comment above as I do not have enough reputation, but the above answer was nearly perfect for me, except I had to add
type: "POST"
to the .ajax call. I was scratching my head for a few minutes trying to figure out what I had done wrong, that's all it needed and works a treat. So this is the whole snippet:
Full credit to the answer above me, this is just a small tweak to that. This is just in case anyone else gets stuck and can't see the obvious.
$.ajax({ url: 'Your url here', data: formData, type: "POST", //ADDED THIS LINE // THIS MUST BE DONE FOR FILE UPLOADING contentType: false, processData: false, // ... Other options like success and etc })
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