How to use ES6 Fat Arrow to .filter() an array of objects

Question

It appears I cannot use an if statement.

Arrow functions either allow to use an expression or a block as their body. Passing an expression

foo => bar

is equivalent to the following block

foo => { return bar; }

However,

if (person.age > 18) person

is not an expression, if is a statement. Hence you would have to use a block, if you wanted to use if in an arrow function:

foo => {  if (person.age > 18) return person; }

---

While that technically solves the problem, this a confusing use of .filter, because it suggests that you have to return the value that should be contained in the output array. However, the callback passed to .filter should return a Boolean, i.e. true or false, indicating whether the element should be included in the new array or not.

So all you need is

family.filter(person => person.age > 18);

In ES5:

family.filter(function (person) {
  return person.age > 18;
});

You can't implicitly return with an if, you would need the braces:

let adults = family.filter(person => { if (person.age > 18) return person} );

It can be simplified though:

let adults = family.filter(person => person.age > 18);

As simple as you can use const adults = family.filter(({ age }) => age > 18 );

const family =[{"name":"Jack",  "age": 26},
              {"name":"Jill",  "age": 22},
              {"name":"James", "age": 5 },
              {"name":"Jenny", "age": 2 }];

const adults = family.filter(({ age }) => age > 18 );

console.log(adults)

Here is my solution for those who use hook; If you are listing items in your grid and want to remove the selected item, you can use this solution.

var list = data.filter(form => form.id !== selectedRowDataId);
setData(list);

return arrayname.filter((rec) => rec.age > 18)

Write this in the method and call it