Is there a way to assign a value to a specific column within a data frame? e.g.,
dat2 = data.frame(c1 = 101:149, VAR1 = 151:200)
j = "dat2[,"VAR1"]" ## or, j = "dat2[,2]"
assign(j,1:50)
The approach above doesn't work. Neither does this:
j = "dat2"
assign(get(j)[,"VAR1"],1:50)
DataFrame - assign() function The assign() function is used to assign new columns to a DataFrame. Returns a new object with all original columns in addition to new ones. Existing columns that are re-assigned will be overwritten. The column names are keywords.
To select a single column, use square brackets [] with the column name of the column of interest.
You can use the loc and iloc functions to access columns in a Pandas DataFrame. Let's see how. If we wanted to access a certain column in our DataFrame, for example the Grades column, we could simply use the loc function and specify the name of the column in order to retrieve it.
Select Cell Value from DataFrame Using df['col_name']. values[] We can use df['col_name']. values[] to get 1×1 DataFrame as a NumPy array, then access the first and only value of that array to get a cell value, for instance, df["Duration"].
lets assume that we have a valid data.frame with 50 rows in each
dat2 <- data.frame(c1 = 1:50, VAR1 = 51:100)
1 . Don't use assign
and get
if you can avoid it.
"dat2[,"VAR1"]"
is not valid in R
.
You can also note this from the help page for assign
assign does not dispatch assignment methods, so it cannot be used to set elements of vectors, names, attributes, etc.
Note that assignment to an attached list or data frame changes the attached copy and not the original object: see attach and with.
A column of a data.frame is an element of a list
What you are looking for is [[<-
# assign the values from column (named element of the list) `VAR1`
j <- dat2[['VAR1']]
If you want to assign new values to VAR1
within dat2
,
dat2[['VAR1']] <- 1:50
To manipulate entirely using character strings using get
and assign
assign('dat2', `[[<-`(get('dat2'), 'VAR1', value = 2:51))
if you want to assign by reference within a data.frame
or data.table
(replacing an existing column only) then set
from the data.table
package works (even with data.frames
)
library(data.table)
set(dat2, j = 'VAR1', value = 5:54)
eval
and bquote
dat1 <- data.frame(x=1:5)
dat2 <- data.frame(x=2:6)
for(x in sapply(c('dat1','dat2'),as.name)) {
eval(bquote(.(x)[['VAR1']] <- 2:6))
}
eapply
Or if you use a separate environment
ee <- new.env()
ee$dat1 <- dat1
ee$dat2 <- dat2
# eapply returns a list, so use list2env to assign back to ee
list2env(eapply(ee, `[[<-`, 'y', value =1:5), envir = ee)
set2 <- function(x, val) {
eval.parent(substitute(x <- val))
}
> dat2 = data.frame(c1 = 101:150, VAR1 = 151:200)
> set2(dat2[["VAR1"]], 1:50)
> str(dat2)
'data.frame': 50 obs. of 2 variables:
$ c1 : int 101 102 103 104 105 106 107 108 109 110 ...
$ VAR1: int 1 2 3 4 5 6 7 8 9 10 ...
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