how to unzip an uploaded zip file using spring in java

Question

I am uploading zip folder from screen and I am sending it to contoller using MultipartFile.I am trying to extract the uploaded folder and saving that extracted folder in some specific location..I tried but I am not getting....Can anyone suggest me? here is my code

 public  String test(
                @RequestParam("datafile") MultipartFile file
    { 

    String source =file.getOriginalFilename();

    //source variable will containthe value as "zip_Folder.zip";
            String destination = "D:\\destination";

            try {
                 ZipFile zipFile = new ZipFile(source);
                 zipFile.extractAll(destination);

            } catch (ZipException e) {
                e.printStackTrace();
            }
    }

Answer 1

Required zip4j and Apache Commons-IO dependencies:

@PostMapping("/upload")
public String add(@RequestParam("file") MultipartFile file) throws IOException {

    /**
     * save file to temp
     */
    File zip = File.createTempFile(UUID.randomUUID().toString(), "temp");
    FileOutputStream o = new FileOutputStream(zip);
    IOUtils.copy(file.getInputStream(), o);
    o.close();

    /**
     * unizp file from temp by zip4j
     */
    String destination = "D:\\destination";
    try {
         ZipFile zipFile = new ZipFile(zip);
         zipFile.extractAll(destination);
    } catch (ZipException e) {
        e.printStackTrace();
    } finally {
        /**
         * delete temp file
         */
        zip.delete();
    }

    return "redirect:/";
}

As addition to that, the best is to place constants like "D:\destination" in properties file and inject by @Value

@Value("${destination.dir}")
private String destination;