How to unwrap a discriminated union without pattern matching?

Question

I have a discriminated union like this:

Type Result =
| Good of bool | Bad of bool

In many cases I know that result is Good. To unwrap the Result, I have to use pattern matching for just the Good option. As a result I get a warning (not an error) that says "Incomplete pattern match on this expression..". Is there a way to unwrap is without having to use pattern matching?

Answer 1

You can just use let, e.g.

type Result =
    | Good of bool 
    | Bad of bool

let example = Good true

let (Good unwrappedBool) = example

Note that this will still result in a compiler warning that the match cases might be incomplete.

Technically, however, this is still using pattern matching, just doing so without a match expression.