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I'm writing a DSL where the "+" operator is strictly numeric, like some other popular languages. It's close, but the String "+" operator is messing up my implicit conversions. What's the syntax for unimporting an operator of the String class?
Just to be clearer, instead of this:
scala> var x = "2" + 3; x: java.lang.String = 23
I'd like to get x: Int = 5
I imagine I just need 2 things to make that happen:
I'm stuck on the first step.
Thanks
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Creating a Stringvar greeting = "Hello world!"; or var greeting:String = "Hello world!"; Whenever compiler encounters a string literal in the code, it creates a String object with its value, in this case, “Hello world!”.
Scala string is an immutable object that means the object cannot be modified. Each element of a string is associated with an index number. The first character is associated with the number 0, the second with the number 1, etc. Class java. lang.
Syntax. var myVar = 10; val myVal = "Hello, Scala!"; Here, by default, myVar will be Int type and myVal will become String type variable.
Console. readChar , aliased in in current incarnations of Scala as Predef. getChar is the most direct way. scala> readChar res0: Char = !
According to section 12.3.1 of the Scala spec, the + method for String has special treatment by the compiler. I don't know for sure, but I think this means you can't "unimport" it, which is a shame because it really breaks the type system (much like the related toString method).
Could you use a different name for the operator in your DSL, eg, ++ or &?
118
The + method for a string is a method on of the String class (and therefore on each string object), and as such it cannot be unimported.
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