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How to toggle elements in and out of DOM using jQuery detach() method?

I have a group of divs arranged in a grid.

enter image description here

To style each div I'm selecting them with the nth-child() pseudo-class.

div.tile:nth-child(4n-7) .text { background-color: yellow; }

A user can hide divs by clicking on a button (which fires a jQuery function that adds a display: none rule to the class attribute in the selected div).

jQuery

$('.hide-divs').click(function () {
     $('.dolphin').toggleClass('hidden');
    })

CSS

.hidden { display: none; }

Here's the problem:

Even though display: none removes the div from the screen, it doesn't remove the div from the DOM, so the nth-child selector still counts it when applying styles, which in turn messes up the visual design of the grid.

enter image description here

The above layout is broken because only the first column should be yellow.

So my first thought was to use the jQuery remove() method, which takes elements (and its descendants) out of the DOM.

Turns out, however, once remove() is applied you can't get those divs back. They're gone. So the toggle function breaks.

After a bit of research I discovered the jQuery detach() method, which does the same thing as .remove(), except it stores the removed elements' data for later use.

From the jQuery website:

The .detach() method is the same as .remove(), except that .detach() keeps all jQuery data associated with the removed elements. This method is useful when removed elements are to be reinserted into the DOM at a later time.

Everything looks good for detach() to work with the toggle switch, except my efforts to implement it aren't working.

I've used the example on the jQuery website as a guide but it doesn't work on the grid. I also read various related posts on this site, but to no avail. I must be missing something.

Any feedback would be much appreciated.

http://jsfiddle.net/tfyfpbb2/

$('.hide-divs').click(function() {
  $('.dolphin').toggleClass('hidden');
})
.row {
  display: flex;
  flex-wrap: wrap;
  width: 500px;
  padding: 0;
  margin: 0;
}
.text {
  height: 50px;
  width: 100px;
  margin: 10px;
  padding-top: 15px;
  background: tomato;
  color: #fff;
  text-align: center;
  font-size: 2em;
}
.tile:nth-child(4n-7) .text {
  border: 2px solid #ccc;
  background-color: yellow;
  color: #000;
}
button {
  padding: 10px;
  background-color: lightblue;
  position: relative;
  left: 200px;
}
.hidden {
  display: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="container">

  <div class="row">

    <div class="tile">
      <div class="text">01</div>
    </div>

    <div class="tile">
      <div class="text">02</div>
    </div>

    <div class="tile">
      <div class="text dolphin">03</div>
    </div>

    <div class="tile">
      <div class="text">04</div>
    </div>

    <div class="tile">
      <div class="text">05</div>
    </div>

    <div class="tile">
      <div class="text dolphin">06</div>
    </div>

    <div class="tile">
      <div class="text">07</div>
    </div>

    <div class="tile">
      <div class="text dolphin">08</div>
    </div>

    <div class="tile">
      <div class="text">09</div>
    </div>

    <div class="tile">
      <div class="text">10</div>
    </div>

    <div class="tile">
      <div class="text">11</div>
    </div>

    <div class="tile">
      <div class="text">12</div>
    </div>

  </div><!-- end .row -->

  <button type="button" class="hide-divs">HIDE DIVS 3, 6 &amp; 8</button>
like image 816
Michael Benjamin Avatar asked Jan 07 '23 15:01

Michael Benjamin


2 Answers

I suggest still using detach. You can do so with this code:

var divs;

$('.hide-divs').on('click', function () {
    if(divs) {
        $(divs).appendTo('.row');
        divs = null;
    } else {
        divs = $('.dolphin').parent().detach();
    }
});

Then to ensure that the same order is used, I came up with this bit of code:

$('.tile').each(function(i){
    $(this).data('initial-index', i);
});

...

$(divs).each(function(){
    var oldIndex = $(this).data('initial-index');
    $('.tile').eq(oldIndex).before(this);
});

Put it all together and we get this code:

var divs;

$('.tile').each(function(i){
    $(this).data('initial-index', i);
});

$('.hide-divs').on('click', function () {
    if(divs) {
        $(divs).appendTo('.row').each(function(){
            var oldIndex = $(this).data('initial-index');
            $('.tile').eq(oldIndex).before(this);
        });
        divs = null;
    } else {
        divs = $('.dolphin').parent().detach();
    }
});

Demo on jsfiddle: http://jsfiddle.net/tqbzff2v/2/

like image 139
Joseph Marikle Avatar answered Feb 01 '23 14:02

Joseph Marikle


Everyone was close, but here is exactly what you are looking for with your current html markup: http://jsfiddle.net/vs5o5nLb/2/

The trick is setting yourself up ahead of time with what you need to actually toggle, then keeping that information around to insert and detach from.

var $els = $( '.tile' );
var stack = [];
var isShown = true;

$els.each(function() {
    var $this = $( this );
    if ( $this.find('.dolphin').length ) {
        stack.push({
            $el : $this,
            index : $els.index( this )
        });
    }
});

$('.hide-divs').click(function () {
    if ( isShown ) {
        $.each(stack, function() {
            this.$el.detach();
        });
        isShown = false;
    } else {
        $.each(stack, function() {
            $('.tile').eq( this.index ).before( this.$el );
        });
        isShown = true;
    }
});

I hope it helps.

like image 24
sic1 Avatar answered Feb 01 '23 14:02

sic1